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Question

Physics Question on Dimensional Analysis

The dimensional formula for electric flux is

A

[ML2T2]{[ML^2T^2]}

B

[ML3T−3A−1]{[ML^3 T^{-3} A^{-1}]}

C

[ML−3T3A1]{[ML^{-3} T^{3} A^{1}]}

D

[ML−1T3A−2]{[ML^{-1} T^{3} A^{-2}]}

Answer

[ML3T−3A−1]{[ML^3 T^{-3} A^{-1}]}

Explanation

Solution

Electric flux, ϕ=E⃗.s⃗\phi = \vec{E} . \vec{s}
Taking dimensions both side, we get
[ϕ]=[MLT−3A−1][L2]=[ML3T−3A−1]{[ \phi] = [MLT^{-3} A^{-1}] [L^2] = [ML^3T^{-3} A^{-1}]}