Question
Physics Question on Electromagnetic induction
The dimension of mutual inductance is :
A
[ML2T-2A-1]
B
[ML2T-3A-1]
C
[ML2T-2A-2]
D
[ML2T-3A-2]
Answer
[ML2T-2A-2]
Explanation
Solution
The correct answer is (C) : [ML2T–2A–2]
∵ U = 21 Mi²
⇒ [M] = [i2][U] = A2ML2T−2
= [ML2T–2A–2]