Solveeit Logo

Question

Physics Question on Dimensional Analysis

The dimension of magnetic flux is

A

[MLT1A1] [MLT^{-1}A^{-1}]

B

[ML1TA2] [ML^{-1}TA^{-2}]

C

[ML2T2A2] [ML^{-2}T^{2}A^{-2}]

D

[ML2T2A1] [ML^{2}T^{-2}A^{-1}]

Answer

[ML2T2A1] [ML^{2}T^{-2}A^{-1}]

Explanation

Solution

Magnetic flux (ϕ)=((\phi)=( Magnetic field) )×() \times( Area )) or [ϕ]=[B][A][\phi]=[B][A]
=[ Force ][ Area ][ Current ][ Length ]=[MLT2][L2][A][L]=\frac{[\text { Force }][\text { Area }]}{[\text { Current }][\text { Length }]}=\frac{\left[M L T^{-2}\right]\left[L^{2}\right]}{[A][L]}
ϕ=[ML2T2A1]|\phi|=\left[M L^{2} T^{-2} A^{-1}\right]