Question
Mathematics Question on General and Particular Solutions of a Differential Equation
The differential equation of the family of parabolas y2=4ax, where a is parameter, is
A
dxdy=2xy
B
dxdy=−2xy
C
dxdy=−y2x
D
dxdy=y2x
Answer
dxdy=2xy
Explanation
Solution
Given equation of parabola is y2=4ax ... (i)
Differentiating (i) w.r.t. x, we get
2ydxdy=4a
⇒dxdy=y2a⇒a=2ydxdy
Substituting the value of a in (i), we get
y2=4.2ydxdyx
⇒y2=2xydxdy⇒dxdy=2xy