Question
Question: The differential equation of the family of circles passing through the points (0, 0) and (a, 0) is...
The differential equation of the family of circles passing through the points (0, 0) and (a, 0) is
A
(x² – y² – ax) dy/dx = (2)(x – a) y
B
(x² + y²) dy/dx = (2)(x – a) dy/dx
C
(x² + y²) dy/dx = (2)(a – x)y
D
None of these
Answer
(x² – y² – ax) dy/dx = (2)(x – a) y
Explanation
Solution
equation of circle is x(x – a) + y2 + ly = 0
̃ x2 + y2 – ax + ly = 0 …(1)
deferential
2x + 2y y' – a + ly' = 0 …(2))
from (1) and (2))yx2+y2−ax=y′2x+2yy′−a
̃ (x2 + y2 – ax) y' = (2)x + 2y y' – a) y
̃ (x2 – y2 – ax) y' = (2)x – a)y