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Question

Question: The differential equation of the family of circles passing through the points (0, 0) and (a, 0) is...

The differential equation of the family of circles passing through the points (0, 0) and (a, 0) is

A

(x² – y² – ax) dy/dx = (2)(x – a) y

B

(x² + y²) dy/dx = (2)(x – a) dy/dx

C

(x² + y²) dy/dx = (2)(a – x)y

D

None of these

Answer

(x² – y² – ax) dy/dx = (2)(x – a) y

Explanation

Solution

equation of circle is x(x – a) + y2 + ly = 0

̃ x2 + y2 – ax + ly = 0 …(1)

deferential

2x + 2y y' – a + ly' = 0 …(2))

from (1) and (2))x2+y2axy=2x+2yyay\frac{x^{2} + y^{2} - ax}{y} = \frac{2x + 2yy' - a}{y'}

̃ (x2 + y2 – ax) y' = (2)x + 2y y' – a) y

̃ (x2 – y2 – ax) y' = (2)x – a)y