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Question

Question: The differential equation of all straight lines passing through the point \(( 1 , - 1 )\)is...

The differential equation of all straight lines passing through the point (1,1)( 1 , - 1 )is

A

y=(x+1)dydx+1y = ( x + 1 ) \frac { d y } { d x } + 1

B

y=(x+1)dydx1y = ( x + 1 ) \frac { d y } { d x } - 1

C

y=(x1)dydx+1y = ( x - 1 ) \frac { d y } { d x } + 1

D

y=(x1)dydx1y = ( x - 1 ) \frac { d y } { d x } - 1

Answer

y=(x1)dydx1y = ( x - 1 ) \frac { d y } { d x } - 1

Explanation

Solution

Since the equation of line passing through (1,–1) is y+1=m(x1)y + 1 = m ( x - 1 )

y+1=dydx(x1)y + 1 = \frac { d y } { d x } ( x - 1 )y=(x1)dydx1y = ( x - 1 ) \frac { d y } { d x } - 1 .