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Question

Question: The differential equation of all non-vertical lines in a plane is: A. \[\dfrac{{{d^2}y}}{{d{x^2}}}...

The differential equation of all non-vertical lines in a plane is:
A. d2ydx2=0\dfrac{{{d^2}y}}{{d{x^2}}} = 0
B. d2xdy2=0\dfrac{{{d^2}x}}{{d{y^2}}} = 0
C. dydx=0\dfrac{{dy}}{{dx}} = 0
D. dxdy=0\dfrac{{dx}}{{dy}} = 0

Explanation

Solution

Hint: First we write the general equation of non-vertical lines in a plane and then differentiate the equation two times with respect to y and after that we get our answer of The differential equation of all non-vertical lines in a plane. We can also calculate it with a different method.

Complete step-by-step solution
The general equation of non-vertical lines in a plane is
ax+by+c=0 where b0  ax + by + c = 0 \\\ {\text{where}} \\\ b \ne 0 \\\
On differentiating the equation with respect to y we get
a+bdydx=0  a + b\dfrac{{dy}}{{dx}} = 0 \\\
Again differentiating the equation with respect to y, we get
bd2ydx2=0 d2ydx2=0  {\text{b}}\dfrac{{{d^2}y}}{{d{x^2}}} = 0 \\\ \Rightarrow \dfrac{{{d^2}y}}{{d{x^2}}} = 0 \\\
Since we get the right answer
Hence option A is the correct answer.

Note: First write the general equation of non-vertical lines in a plane which is ax+by+c=0ax + by + c = 0 where. We have to remember this formula. Then differentiated it with respect to yy and we get a+bdydx=0a + b\dfrac{{dy}}{{dx}} = 0 and by differentiating again we get dy2dx2=0\dfrac{{d{y^2}}}{{d{x^2}}} = 0 we get our answer. We can also solve this problem by using the equation y=mx+cy = mx + c so and differentiate the equation two times with respect to yy we will get the same correct answer.