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Question: The differential equation of all circles of radius a is of order...

The differential equation of all circles of radius a is of order

A

2

B

3

C

4

D

None of these

Answer

2

Explanation

Solution

The equation of the family of circles of radius a is (x−h)2+(y−k)2=a2( x - h ) ^ { 2 } + ( y - k ) ^ { 2 } = a ^ { 2 }which is a two parameter family of curves. So its differential equation is of order two.