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Question: The differential equation of all circles in the first quadrant which touch the coordinate axes is of...

The differential equation of all circles in the first quadrant which touch the coordinate axes is of order

A

2

B

3

C

4

D

None of these

Answer

2

Explanation

Solution

The equation of the family of circle which touch both the axes is (xa)2+(ya)2=a2( x - a ) ^ { 2 } + ( y - a ) ^ { 2 } = a ^ { 2 }where a is a parameter. This is one parameter family of curves. So its differential equation is of order one.