Question
Question: The differential equation found by the elimination of the arbitrary constant K from the equation \(...
The differential equation found by the elimination of the arbitrary constant K from the equation y=(x+K)e−x is
A
dxdy−y=e−x
B
dxdy−yex=1
C
dxdy+yex=1
D
dxdy+y=e−x
Answer
dxdy+y=e−x
Explanation
Solution
y=(x+K)e−x ⇒ dxdy=−(x+K)e−x+e−x
⇒ dxdy=−y+e−x ⇒ dxdy+y=e−x.