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Question: The differential Coefficient of ƒ(log<sub>e</sub> x) w.r.t x, where ƒ(x) = log<sub>e</sub> x is –...

The differential Coefficient of ƒ(loge x) w.r.t x, where

ƒ(x) = loge x is –

A

x/loge x

B

loge x/x

C

(x loge x)–1

D

None

Answer

(x loge x)–1

Explanation

Solution

Let u = ƒ(loge x)

\ dudx\frac{du}{dx} = ƒ¢ (loge x) . 1x\frac{1}{x} … (1)

given ƒ(x) = loge x

\ Ģ(x) = 1x\frac{1}{x}

\ ƒ¢(loge x) = 1logex\frac{1}{\log_{e}x} … (2)

From (1) and (2),

dudx\frac{du}{dx} = 1xlogex\frac{1}{x\log_{e}x}

= (x loge x)–1.