Question
Question: The differential coefficient of \(\log (\tan x)\) is \( {\text{A}}{\text{. 2sec2}}x \\\ {\...
The differential coefficient of log(tanx) is
A. 2sec2x B. 2cosec2x C. 2sec2x D. 2cosec2x
Solution
Hint:- In this question first we need to let the given function equal to y. Then, we have to find a differential coefficient which is also called derivative dxd(f(x)). After finding the derivative we have to convert it into form which matches with one of the given options.
Complete step-by-step answer:
Let y= log(tanx). --- Eq.1
Now the differential coefficient of y is given by
⇒dxdy
Now on differentiating eq.1 with respect to x
We get
⇒dxdy=dxdlog(tanx) ---- eq.2
We know
⇒dxdlogx=x1 ---- eq.3
⇒dxdtanx=sec2x ----eq.4
Using eq.3 and eq.4 and chain rule, we get
⇒dxdy=tanx1.sec2x
We know tanx=cosxsinx and sec2x=cos2x1
The above equation can be written as
⇒dxdy=(sinxcosx).cos2x1 ⇒dxdy=sinx.cosx1
Multiply “2” in both denominator and numerator we get
⇒dxdy=2sinx.cosx2 ---- eq.5
We know,
⇒2sinx.cosx=sin2x
Andsin2x1=cosec2x
Using above equations we can rewrite eq.5 as
⇒dxdy=2cosec2x
Therefore, the differential coefficient of log(tanx) is 2cosec2x.
Hence option B. is correct.
Note:- Whenever you get this type of question the key concept to solve this is to learn concept the differential coefficient (derivativedxd(f(x))) and the derivatives of most basic functions . And remember one more thing that a coefficient is usually a constant quantity, but the differential coefficient of function is a constant function only if function is a linear function.