Question
Question: The differential coefficient of \[f(\log x)\] , where \[f(x) = \log x\] , is A) \[\dfrac{x}{{x\log...
The differential coefficient of f(logx) , where f(x)=logx , is
A) xlogxx
B) (xlogx)−1
C) xxlogx
D) None of these
Solution
Differentiation of logarithmic functions are mainly based on the chain rule. We can generalize any differentiable function with a logarithmic function. Differentiation of any constant is zero. Differentiation of a constant and a function is equal to constant times the differentiation of the function. The differentiation of log is only under the base e but we can differentiate under other bases. Derivative of logx is given as dxdlogx=x1.
Complete step-by-step solution:
It is given in the question that f(x)=logx.
So, we have to find the composite function f(logx) first and then differentiate it with respect to x.
So, we substitute the value of x as logx in the function. So, we get,
⇒f(logx)=loglogx
Now, we have to differentiate this composite function with respect to x.
Now, Let us assume u=logx. So substituting logx as u, we get,
⇒f(logx)=log(u)
Differentiating both sides with respect to x, we get,
⇒dxd[f(logx)]=dxd[log(u)]
We know that the derivative of logarithmic function (logx) with respect to x is x1.
⇒dxd[f(logx)]=(u1)dxdu
Now, substituting back u as logx, we get,
⇒dxd[f(logx)]=(logx1)dxd(logx)
⇒dxd[f(logx)]=(logx1)(x1)
So, simplifying the expression, we get,
⇒dxd[f(logx)]=(xlogx1)
This can further be written as f′(logx)=(xlogx)−1
Hence, option B is the correct answer.
Note: The slope is the rate of change of y with respect to x that means if x is increased by an additional unit the change in y is given by dxdy. Let us understand with an example, the rate of change of displacement of an object is defined as the velocity hrKm that means when time is increased by one hour the displacement changes by a kilometre. For solving derivative problems different techniques of differentiation must be known thoroughly.