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Question

Physics Question on Ray optics and optical instruments

The difference of speed of light in the two media A and B(υA – υB) is 2.6 × 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is: (Given: speed of light in vacuum C = 3 × 108 ms–1)

A

1.303

B

1.318

C

1.13

D

0.12

Answer

1.13

Explanation

Solution

Speed of light in a medium = cn\frac cn
According to the question
cnAcnB=2.6×107\frac {c}{n_A} - \frac {c}{n_B} = 2.6×10^7

nBnA1=2.6×1073×108×nB⇒ \frac {n_B}{n_A}−1 = \frac {2.6×10^7}{3×10^8}×n_B

nBnA1.13⇒ \frac {n_B}{n_A} ≃ 1.13

So, the correct option is (C): 1.131.13