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Question: The difference between heats of reaction at constant pressure and constant volume for the reaction ...

The difference between heats of reaction at constant pressure and constant volume for the reaction

2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l)2C_{6}H_{6}(l) + 15O_{2}(g) \rightarrow 12CO_{2}(g) + 6H_{2}O(l) at

25oC25^{o}C in kJ is

A

–7.43

B

+3.72+ 3.72

C

−3.72- 3.72

D

+7.43+ 7.43

Answer

–7.43

Explanation

Solution

Δng=12−15=−3\Delta n_{g} = 12 - 15 = - 3

qP−qv=ΔngRT=−3×8.3141000×298=−7.43kJ.\mathbf{q}_{\mathbf{P}}\mathbf{-}\mathbf{q}_{\mathbf{v}}\mathbf{= \Delta}\mathbf{n}_{\mathbf{g}}\mathbf{RT = - 3 \times}\frac{\mathbf{8.314}}{\mathbf{1000}}\mathbf{\times 298}\mathbf{=}\mathbf{-}\mathbf{7.43kJ.}