Question

The dielectric strength of a medium is $2\,kVmm^{-1}$ . What is the maximum potential difference that can be set up across a $50\,pm$ specimen without puncturing it.

• A. 10 V
• B. 100 V
• C. 1000 V
• D. 10000 V

Answer 1

Answer: (B)

100 V

Answer 2

Dielectric strength = Potential difference gradient. Hence maximum potential difference = Dielectric strength $\times$ distance = $\frac{2000\, V}{mm} \times 50 \, \mu m = \frac{2000 \, V}{10^{-3} \, m} \times 50 \times 10^{-6} m$ = 100 V.