Question

The dielectric constants of ${{\text{H}}_{\text{2}}}\text{O}$ and ${{\text{D}}_{\text{2}}}\text{O}$ are 82 and 80.5 respectively. Therefore, the solubility of NaCI in ${{\text{D}}_{\text{2}}}\text{O}$ is ...... than in water:

• A. equal to
• B. slightly less
• C. slightly higher
• D. very high

Answer 1

Answer: (B)

slightly less

Answer 2

Greater the value of dielectric constant, greater will be the polarity of the solvent. Hence, water is more polar than ${{\text{D}}_{\text{2}}}\text{O}\text{.}$ So, $\text{NaCl}$ is more soluble in ${{\text{H}}_{\text{2}}}\text{O}$ in comparison to ${{\text{D}}_{\text{2}}}\text{O}\text{.}$