Question
Question: The diameter of the circle \(x^{2} + y^{2} - 4x + 2y - 11 = 0\) corresponding to a system of chords ...
The diameter of the circle x2+y2−4x+2y−11=0 corresponding to a system of chords parallel to the line x−2y+1=0
A
x−2y+3=0
B
2x−y+3=0
C
2x+y−3=0
D
None of these
Answer
2x+y−3=0
Explanation
Solution
The centre of the given circle is (2, –1) the equation of the line perpendicular to chord x−2y+1=0 is 2x+y+k=0
Since the line passes through the point (2, –1)
therefore k = – 3. The equation of diameter is 2x+y−3=0.