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Question: The diameter of the circle \(x^{2} + y^{2} - 4x + 2y - 11 = 0\) corresponding to a system of chords ...

The diameter of the circle x2+y24x+2y11=0x^{2} + y^{2} - 4x + 2y - 11 = 0 corresponding to a system of chords parallel to the line x2y+1=0x - 2y + 1 = 0

A

x2y+3=0x - 2y + 3 = 0

B

2xy+3=02x - y + 3 = 0

C

2x+y3=02x + y - 3 = 0

D

None of these

Answer

2x+y3=02x + y - 3 = 0

Explanation

Solution

The centre of the given circle is (2, –1) the equation of the line perpendicular to chord x2y+1=0x - 2y + 1 = 0 is 2x+y+k=02x + y + k = 0

Since the line passes through the point (2, –1)

therefore k = – 3. The equation of diameter is 2x+y3=0.2x + y - 3 = 0.