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Question: The diagonals AC and BD of a rhombus intersect at (5, 6). If A = (3, 2) then equation of diagonal BD...

The diagonals AC and BD of a rhombus intersect at (5, 6). If A = (3, 2) then equation of diagonal BD is-

A

y – x = 1

B

2y – x = 17

C

y – 2x + 4 = 0

D

2y + x = 17

Answer

2y + x = 17

Explanation

Solution

Slope of BD = –1slopeofAC\frac{–1}{slopeofAC}

m = –1/6–15–3–1/\frac{6–1}{5–3}= –12–\frac{1}{2}

Equation of BD y – 6 = –12–\frac{1}{2} (x – 5)

2y – 12 = – x + 5 Ž x+2y–17=0\begin{matrix} x + 2y–17 = 0 \end{matrix}