Question

The depth at which the effective value of acceleration due to gravity is $\frac { g } { 4 }$is $( R$ = radius of the earth)

• A. R
• B. $\frac { 3 R } { 4 }$
• C.
• D. $\frac { R } { 4 }$

Answer 1

Answer: (B)

$\frac { 3 R } { 4 }$

Answer 2

$g ^ { \prime } = g \left( 1 - \frac { d } { R } \right)$ ⇒ $\frac { g } { 4 } = g \left( 1 - \frac { d } { R } \right)$ $\Rightarrow d = \frac { 3 R } { 4 }$