Question

The depletion layer in a silicon diode is $1\,\mu m$ wide and its knee potential is $0.6\,V$, then the electric field in the depletion layer will be

• A. $0.6\,V/m$
• B. $6\times 10^{4}\,V/m$
• C. $6\times 10^{5}\,V/m$
• D. zero

Answer 1

Answer: (C)

$6\times 10^{5}\,V/m$

Answer 2

$E=-\frac{dV}{dr}=\frac{0.6}{10^{-6}}$
$=6\times 10^{5}V/m$