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Question: The density of water is \( 1.0\dfrac{g}{{mL}} \) . What is the density of water in \( \dfrac{{pounds...

The density of water is 1.0gmL1.0\dfrac{g}{{mL}} . What is the density of water in poundsgallon\dfrac{{pounds}}{{gallon}} ?

Explanation

Solution

The question of dimensional analysis. You have to convert gmL\dfrac{g}{{mL}} into poundsgallon\dfrac{{pounds}}{{gallon}} that is 1gmL×??=poundsgal\dfrac{{1g}}{{mL}} \times \mathop {\dfrac{?}{?}}\limits_{} = \dfrac{{pounds}}{{gal}} . The question mark is the conversion factor that you need to find out to convert. Remember that 1 ponds=453.6g1{\text{ }}ponds = 453.6g and 1 gallon=3785.411 mL1{\text{ }}gallon = 3785.411{\text{ }}mL . Use these values to convert grams per milliliters to pounds per gallons.

Complete Step By Step Answer:
This is the question of dimensional analysis. The study of the relationship between physical quantities with the help of dimensions and units of measurement is termed dimensional analysis. The basic concept of dimension is that we can add and subtract only those quantities that have the same dimensions.
You need to convert gmL\dfrac{g}{{mL}} into poundsgallon\dfrac{{pounds}}{{gallon}} . Find a conversion factor that can be multiplied with the gmL\dfrac{g}{{mL}} units to give the value in poundsgallon\dfrac{{pounds}}{{gallon}} .
Here mass conversation unit gpoundsg \to pounds and volume conversation unit mLgalmL \to gal is required. It is known that for mass, 1 ponds=453.6g1{\text{ }}ponds = 453.6g and for volume 1 gallon=3785.411 mL1{\text{ }}gallon = 3785.411{\text{ }}mL . For our solving purpose we will write it as: 1pounds453.6g\dfrac{{1pounds}}{{453.6g}} and 3785.411 mL1gal\dfrac{{3785.411{\text{ }}mL}}{{1gal}} . These two will be our conversion factors that will be multiplied with the gmL\dfrac{g}{{mL}} unit.
Now that we know the conversion factors to be multiplied, we will apply them and find out the final result.
1gmL×1  pounds453.6g×3785.411  mL1gal=8.34poundsgal\dfrac{{1g}}{{mL}} \times \dfrac{{1\;pounds}}{{453.6g}} \times \dfrac{{3785.411\;mL}}{{1gal}} = \dfrac{{8.34pounds}}{{gal}}
Therefore the density of water in poundsgallon\dfrac{{pounds}}{{gallon}} is 8.34poundsgal\dfrac{{8.34pounds}}{{gal}} .

Note:
Dimensional analysis has limitations also. It doesn’t give information about the dimensional constant. It gives no information about whether a physical quantity is a scalar or vector. The formula containing trigonometric function, exponential functions, logarithmic function, etc. cannot be derived.