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Question: The density of mercury is \(13.6g/mL\). Calculate the diameter of an atom of mercury assuming that e...

The density of mercury is 13.6g/mL13.6g/mL. Calculate the diameter of an atom of mercury assuming that each atom of mercury is occupying a cube of edge-length equal to the diameter of mercury atom. (Atomic mass of mercury = 200)

Explanation

Solution

The density of an atom is equal to the ratio of mass of the atom and the volume of the atom. One mole of mercury contains 6.023×10236.023 \times {10^{23}} number of atoms. Here the diameter of one atom has to be determined.

Complete step by step answer: Let the diameter of one atom of mercury be xx.
As given each atom of mercury is occupying a cube of edge length equal to the diameter of mercury atom, so the volume of mercury atom = volume of cube = x3{x^3}
The atomic mass of mercury = 200
The density of mercury = 13.6 g/mL
One mole of mercury contains 6.023×10236.023 \times {10^{23}}atoms.
As density=massvolumedensity = \dfrac{{mass}}{{volume}}
Volume of one mercury atom = x3{x^3}
So volume of 6.023×10236.023 \times {10^{23}} atoms = x3×6.023×1023{x^3} \times 6.023 \times {10^{23}}
Inserting the values,
13.6=200x3×6.023×102313.6 = \dfrac{{200}}{{{x^3} \times 6.023 \times {{10}^{23}}}}
x3=20013.6×6.023×1023{x^3} = \dfrac{{200}}{{13.6 \times 6.023 \times {{10}^{23}}}}
x3=24.416×1024{x^3} = 24.416 \times {10^{ - 24}}
x=2.9×108cmx = 2.9 \times {10^{ - 8}}cm
Hence the diameter of an atom of mercury is 2.9×108cm2.9 \times {10^{ - 8}}cm.

Note: Atomic weight of a substance is equal to the Avogadro’s number for the substance. Thus it is said that one mole of a substance is taken or used that means the amount of weight equal to the atomic or molecular weight is considered. Density of a substance is a relative property with respect to density of water which is 1.00 g/mL1.00{\text{ }}g/mL. Mercury is silvery white liquid metal used in thermometers, barometers etc. due to its high density. Mercury is very toxic if inhaled.