Question
Question: The density of mercury is \(13.6g/mL\). Calculate the diameter of an atom of mercury assuming that e...
The density of mercury is 13.6g/mL. Calculate the diameter of an atom of mercury assuming that each atom of mercury is occupying a cube of edge-length equal to the diameter of mercury atom. (Atomic mass of mercury = 200)
Solution
The density of an atom is equal to the ratio of mass of the atom and the volume of the atom. One mole of mercury contains 6.023×1023 number of atoms. Here the diameter of one atom has to be determined.
Complete step by step answer: Let the diameter of one atom of mercury be x.
As given each atom of mercury is occupying a cube of edge length equal to the diameter of mercury atom, so the volume of mercury atom = volume of cube = x3
The atomic mass of mercury = 200
The density of mercury = 13.6 g/mL
One mole of mercury contains 6.023×1023atoms.
As density=volumemass
Volume of one mercury atom = x3
So volume of 6.023×1023 atoms = x3×6.023×1023
Inserting the values,
13.6=x3×6.023×1023200
x3=13.6×6.023×1023200
x3=24.416×10−24
x=2.9×10−8cm
Hence the diameter of an atom of mercury is 2.9×10−8cm.
Note: Atomic weight of a substance is equal to the Avogadro’s number for the substance. Thus it is said that one mole of a substance is taken or used that means the amount of weight equal to the atomic or molecular weight is considered. Density of a substance is a relative property with respect to density of water which is 1.00 g/mL. Mercury is silvery white liquid metal used in thermometers, barometers etc. due to its high density. Mercury is very toxic if inhaled.