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Question: The density of material in CGS system of units is \(3 g / \mathrm{cm}^{3} .\) In a system of units i...

The density of material in CGS system of units is 3g/cm3.3 g / \mathrm{cm}^{3} . In a system of units in which unit of length is 10 cm10 \mathrm{~cm} and unit of mass is 100 g,100 \mathrm{~g}, the value of density of material will be
A.0.40.4
B.30
C.400
D.0.04

Explanation

Solution

First of all we will convert the 3 g3 \mathrm{~g} mass into the 100 g100 \mathrm{~g} scale and the 1 cm1 \mathrm{~cm} length into the 10 cm10 \mathrm{~cm} scale to find the equivalent number of units. In order to find the density in the new system of units, we will then substitute the values required in the density equation.

Formula used:
ρ=mv\rho=\dfrac{m}{v}

Complete answer:
In the question given, the following data is provided:
Material density is given as 3 g cm33 \mathrm{~g} \mathrm{~cm}^{-3} in the CGS system of units.
If the unit of length is 10 cm10 \mathrm{~cm} and the unit of mass is 100 g100 \mathrm{~g}, we are asked to find the density value of the material. To begin with as mentioned in the question, we will first need to convert the units given into the new system of units. The second case says 100 g100 \mathrm{~g} is the unit of mass and 10 cm10 \mathrm{~cm} is the unit of length.
We know,
ρ=mv\rho=\dfrac{m}{v}
Where,
ρ\rho indicates the density of a material.
mm indicates the mass of the material.
vv indicates the volume of the material.
ρ=3 g1 cm3(1)\therefore \rho=\dfrac{3 \mathrm{~g}}{1 \mathrm{~cm}^{3}} \ldots \ldots(1)
When the mass is 100 g100 \mathrm{~g}, then the mass of 4 g4 \mathrm{~g} in a new system of units is equivalent to 3100\dfrac{3}{100} units. Again, when the unit of length is 10 cm,10 \mathrm{~cm}, then 1 cm1 \mathrm{~cm} in a new system of units is equivalent to 110\dfrac{1}{10} units.
Now we can also change the values in the equation (1), which is shown below:
ρ=3×1 g(1 cm)3\rho=\dfrac{3 \times 1 \mathrm{~g}}{(1 \mathrm{~cm})^{3}}
ρ=3×1100(110)3\Rightarrow \rho=\dfrac{3 \times \dfrac{1}{100}}{\left(\dfrac{1}{10}\right)^{3}}
ρ=3100×103\Rightarrow \rho=\dfrac{3}{100} \times 10^{3}
ρ=30units\Rightarrow \rho=30 \mathrm{units}
The value of density of material will be ρ=30units\Rightarrow \rho=30 \mathrm{units}
The correct option (B)

Note:
In the question given, the following data is provided: Material density is given as 4 g cm34 \mathrm{~g} \mathrm{~cm}^{-3} in the CGS system of units. If the unit of length is 10 cm10 \mathrm{~cm} and the unit of mass is 100 g100 \mathrm{~g}, we are asked to find the density value of the material.