Question

The density of ice at 0°C is 0.915 gram/cc and that of liquid water at 0°C is 0.99987 gram/cc. The work done for melting 1 mole of ice at 1.00 bar (assuming work is done only due to expansion) is approximately –

• A. 0.17 J
• B. 1.7 × 10³ J
• C. 1.7 × 10^–6 J
• D. Can't be determined

Answer 1

Answer: (A)

0.17 J

Answer 2

W = – PDV = –10⁵ $\frac{N}{m^{2}}\left\lbrack \frac{18 \times 10^{–6}}{0.99987}m^{3}–\frac{18 \times 10^{–6}}{0.915}m^{3} \right\rbrack$= + 10⁵ × 1.67 × 10^–6 J

= 0.167 J ~ 0.17 J