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Question

Physics Question on Electric Current

The density of copper is 9×103kg/m39 \times 10^3\, kg/m^3 and its atomic mass is 63.5u63.5\, u . Each copper atom provides one free electron. Estimate the number of free electrons per cubic metre in copper,

A

101910^{19}

B

102310^{23}

C

102510^{25}

D

102910^{29}

Answer

102910^{29}

Explanation

Solution

Density of copper,
ρ=9×103kg/m3\rho =9\times 10^{3} kg/m^{3}
=9×106g/m3=9\times 10^{6} g/m^{3}
Avogadro number, NA=6.023×1023N_{A}=6.023\times10^{23}
Mass of 11 mole of copper atom, M=63.5gM=63.5\,g
Thus, number of free electrons per volume is
n=NAMρ=6.023×102363.5×9×106n=\frac{N_{A}}{M} \rho=\frac{6.023\times10^{23}}{63.5}\times9\times10^{6}
=8.5×1028m3=8.5 \times 10^{28}\,m^{-3}