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Question

Question: The density of carbon nucleus \({}_{6}^{12}C\)is –...

The density of carbon nucleus 612C{}_{6}^{12}Cis –

A

2.4 kg/m3

B

2.4 × 1017 kg/m3

C

2.4 × 1012 kg/m3

D

2400 kg/m3

Answer

2.4 × 1017 kg/m3

Explanation

Solution

r = = 12amu(1.66×1027 kg/amu)43πR3\frac { 12 \mathrm { amu } \left( 1.66 \times 10 ^ { - 27 } \mathrm {~kg} / \mathrm { amu } \right) } { \frac { 4 } { 3 } \pi \mathrm { R } ^ { 3 } }

R3 = (R0A1/3)3 = R03\mathrm { R } _ { 0 } ^ { 3 } A = (1.2)3 × (10–15)3 A

r = 12amu(1.66×1027)43π×(1.2×1015)3×12amu\frac { 12 \mathrm { amu } \left( 1.66 \times 10 ^ { - 27 } \right) } { \frac { 4 } { 3 } \pi \times \left( 1.2 \times 10 ^ { - 15 } \right) ^ { 3 } \times 12 \mathrm { amu } } r = 2.4 × 1017 kg/m3