Solveeit Logo

Question

Question: The density of air at N.T.P. is \[1.292\dfrac{gm}{lit}\]. If the pressure is tripled keeping its tem...

The density of air at N.T.P. is 1.292gmlit1.292\dfrac{gm}{lit}. If the pressure is tripled keeping its temperature constant its density becomes

& A.~~~~~~~~~~~~~3.87\dfrac{gm}{ltr} \\\ & B.~~~~~~~~~~~~~1.293\dfrac{gm}{ltr} \\\ & C.~~~~~~~~~~~~~2.586\dfrac{gm}{ltr} \\\ & D.~~~~~~~~~~~~~0.431\dfrac{gm}{ltr} \\\ \end{aligned}$$
Explanation

Solution

Hint: If the temperature of gas is kept constant the density of gas is directly proportional to its pressure. The relation between density and pressure for an ideal gas is given by
d=PMoRTd=\dfrac{P{{M}_{o}}}{RT}, where
Mo{{M}_{o}} is molar mass of gas, P is pressure of gas, T is temperature of gas, d is density of gas, and R is universal gas constant.

Formula Used: Ideal gas equation
PV=nRTPV=nRT, where P is pressure of gas, T is temperature of gas, V is volume of gas, R is universal gas constant and n is number of moles
Density of gas
d=PMoRTd=\dfrac{P{{M}_{o}}}{RT}
Moles of gas is equal to
n=MMon=\dfrac{M}{{{M}_{o}}}

Complete Step By Step Solution:
Density of any substance is mass of substance per unit volume. Therefore
d=MVd=\dfrac{M}{V}
M=dVM=dV … (1)
Where M is mass of gas, V is volume of gas and d is density of gas
We know that for all gases
n=MMon=\dfrac{M}{{{M}_{o}}}, where
n is moles of gas, Mo{{M}_{o}} is molar mass of gas, and M is mass of gas.
Putting value of M from equation 1
n=dVMon=\dfrac{dV}{{{M}_{o}}}
nV=dMo\dfrac{n}{V}=\dfrac{d}{{{M}_{o}}} … (2)
According to ideal gas equation
PV=nRTPV=nRT
nV=PRT\dfrac{n}{V}=\dfrac{P}{RT}
Putting value of nV\dfrac{n}{V} from equation 2
dMo=PRT\dfrac{d}{{{M}_{o}}}=\dfrac{P}{RT}
d=PMoRTd=\dfrac{P{{M}_{o}}}{RT}
Now, according to the question the density of gas was 1.292gmlit1.292\dfrac{gm}{lit} at some pressure. Let us assume that pressure to bePoP{}_{o}.
1.292=PoMoRT1.292=\dfrac{P{}_{o}{{M}_{o}}}{RT} … (3)
Now if the pressure is tripled keeping its temperature constant, let density of gas be d
d=3PoMoRTd=\dfrac{3{{P}_{o}}{{M}_{o}}}{RT}
Putting value PoMoRT\dfrac{P{}_{o}{{M}_{o}}}{RT} from equation 3
d=3×1.292=3.87gmltrd=3\times 1.292=3.87\dfrac{gm}{ltr}
Hence the correct option is A.

Note: It should always be kept in mind that density of gas is proportional to its pressure only when the temperature is kept constant. Also if pressure is kept constant density of gas is inversely proportional to its temperature. Also the formula d=PMoRTd=\dfrac{P{{M}_{o}}}{RT} should be remembered for future problems.