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Question

Physics Question on Nuclear physics

The density of a nucleus of mass number AA is proportional to

A

A3A^{3}

B

A1/3A^{1/3}

C

A1A^{1}

D

AA^{\circ}

Answer

AA^{\circ}

Explanation

Solution

Radius of typing nucleus is given by R=R0A1/3R=R_{0} A^{1 / 3}
So, the volume of the nucleus is given by V=R03AV=R_{0}^{3} A
Hence, the density is given by
ρ=AR30A=1R03\rho=\frac{A}{R_{3}^{0} A}=\frac{1}{R_{0}^{3}}
ρA\rho \propto A