Question

The density of a monobasic strong acid (Molar mass $242 \,g$ mol) is $121 \,kg \,L$ The volume of its solution required for the complete neutralization of $25 \,mL$ of $024\, M\, NaOH$ is ___$\times 10^{-2} mL$ (Nearest integer)

Answer 1

The correct answer is 12
millimole of NaOH=0.24×25
∴ millimole of acid =0.24×25
⇒ mass of acid =0.24×25×24.2mg
for pure acid,
V=dw​;(d=1.21kg/L=1.21g/ml)
∴V=1.120.24×25×24.2​×10−3
=120×10−3ml
=12×10−2ml