Question

The density of a gas at normal pressure and 27°C temperature is 24. Keeping the pressure constant, the density at 127°C will be

• A. 6
• B. 12
• C. 18
• D. 24

Answer 1

Answer: (C)

18

Answer 2

At constant pressure, $\rho T$ = constant

Ž $\frac{\rho_{1}}{\rho_{2}} = \frac{T_{2}}{T_{1}}$ Ž $\frac{24}{\rho_{2}} = \frac{(273 + 127)}{(273 + 27)} = \frac{400}{300}$Ž $\rho_{2} = 18$.