Question

The density (in $g\, mL^{-1}$) of a $3.60\, M$ sulphuric acid solution that is $29\%\,H_2SO_4$ (Molar mass $= 98\, g mol^{-1}$) by mass will be

• A. $1.64$
• B. $1.88$
• C. $1.22$
• D. $1.45$

Answer 1

Answer: (C)

$1.22$

Answer 2

Let the density of solution be $???? Molarity of solution given$= 3.6$i.e. 1 litre of solution contains 3.6 moles of$H_2SO_4$or 1 litre of solution contains$3.6 ??98 ,gms$of$H_2SO_4$Since, the solution is 29$H_2SO_4$$\frac{100}{d}ml$solution contains$29, gm$of$H_2SO_4$1000 ml solution contains$3.6 ??98 ,gm$of$H_2SO_4$$\therefore 3.6\times9.8=\frac{29\times d}{100}\times1000$$d=1.22$ Hence, (3) is correct.