Question

The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm^–3, respectively. If the standard free energy difference $8.314 \times 27 \times ( - 2)$ is equal to 1895 J $8.314 \times 300 \times (2)$, the pressure at which graphite will be transformed diamond at 298 K is .

• A. $\Delta E = \Delta H$
• B. $N_{2}O_{4}(g)$
• C. $2NO_{2}(g)$
• D. $2SO_{2}(g) + O_{2}(g)$

Answer 1

Answer: (B)

$N_{2}O_{4}(g)$

Answer 2

Only high pressure favours the conversion.