Solveeit Logo

Question

Chemistry Question on Gibbs Free Energy

The densities of graphite and diamond at 298K298\, K are 2.252.25 and 3.31gcm3,3.31\, g\, cm^{-3}, respectively. If the standard free energy difference (ΔG)(\Delta G^{\circ}) is equal to 1895Jmol11895\, J\, mol^{-1}, the pressure at which graphite will be transformed into diamond at 298K298\, K is -

A

9.92×108Pa9.92 \times 10^8 \, Pa

B

9.92×107Pa9.92 \times 10^7 \, Pa

C

9.92×106Pa9.92 \times 10^6 \, Pa

D

9.92×105Pa9.92 \times 10^5 \, Pa

Answer

9.92×108Pa9.92 \times 10^8 \, Pa

Explanation

Solution

The pressure at which graphite will be transformed into diamond at 298K is

9.92×108  Pa9.92 \times 10^8 \; Pa