Question

The $\Delta T$ and $\Delta S$ for a reaction at one atmospheric pressure are +30.558 kJ and $\Delta E$ respectively. The temperature at which the free energy change will be zero and below of this temperature the nature of reaction would be.

• A. 483 K, spontaneous
• B. 443 K, non-spontaneous
• C. 443 K, spontaneous
• D. 463 K, non-spontaneous (e) 463 K, spontaneous

Answer 1

Answer: (D)

463 K, non-spontaneous

(e) 463 K, spontaneous

Answer 2

$3kJ$

$(C_{V} = 20J/K)$

or $H_{2(g)} + Cl_{2(g)} \rightarrow 2HCl_{(g)}$

If $\Delta T$ sign $\Delta S$ mean. If is reversible process.