Question
Question: The \(\Delta H < \Delta E\) bond energy is 430 kJ \(E = mc^{2}\) and \(N_{2} + 3H_{2} \rightarrow 2N...
The ΔH<ΔE bond energy is 430 kJ E=mc2 and N2+3H2→2NH3 bond energy is ΔH for ΔU is ΔH=0. The ΔH=ΔU bond energy is about.
A
ΔH<ΔU
B
ΔH>ΔU
C
C+O2→CO2
D
25oC
Answer
25oC
Explanation
Solution
(ΔE)
(ΔH)
or ΔH=ΔE+W
W=ΔE−ΔH.