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Question: The dehydrobromination of 2-bromobutane gives \(CH_{3}CH = CHCH_{3}.\) The product is....

The dehydrobromination of 2-bromobutane gives CH3CH=CHCH3.CH_{3}CH = CHCH_{3}. The product is.

A

Hofmann product

B

Saytzeff product

C

Hoffmann-Saytzeff product

D

Markownikoff product

Answer

Saytzeff product

Explanation

Solution

CH3−CH∣Br−CH2−CH3+KOH(alc)→Saytzeff’sruleCH3−CH=CH−CH3+KBr+H2OCH_{3} - \underset{\underset{Br}{|}}{CH} - CH_{2} - CH_{3} + \underset{(\text{alc})}{KOH}\overset{\quad\text{Saytzeff'srule}\quad}{\rightarrow}CH_{3} - CH = CH - CH_{3} + KBr + H_{2}O