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Question

Mathematics Question on Order and Degree of Differential Equation

The degree of the differential equation y(x)=1+dydx+11.2(dydx)2+11.2.3(dydx)3+.........y(x)=1 +\frac{dy}{dx}+\frac{1}{1.2}\left(\frac{dy}{dx}\right)^2+\frac{1}{1.2.3}\left(\frac{dy}{dx}\right)^3+......... is

A

2

B

3

C

1

D

none of these

Answer

1

Explanation

Solution

Given that
y(x)=1+dydx=11.2(dydx)2+11.2.3(dydx)3+y(x)=1+\frac{d y}{d x}=\frac{1}{1.2}\left(\frac{d y}{d x}\right)^{2}+\frac{1}{1.2 .3}\left(\frac{d y}{d x}\right)^{3}+\ldots \ldots
or y(x)=1+11!(dydx)+12!(dydx)2+13!(dydx)3+y(x)=1+\frac{1}{1 !}\left(\frac{d y}{d x}\right)+\frac{1}{2 !}\left(\frac{d y}{d x}\right)^{2}+\frac{1}{3 !}\left(\frac{d y}{d x}\right)^{3}+\ldots \ldots
y(x)=edy/dxy(x)=e^{d y / d x}
Taking log on both sides, we get
logy(x)=dydx\log y(x)=\frac{d y}{d x}
\therefore The degree of this equation is 11 .