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Question

Question: The degree of the differential equation \(\left( 1 + \left( \frac { d y } { d x } \right) ^ { 2 } ...

The degree of the differential equation

(1+(dydx)2)3/4=(d2ydx2)1/3\left( 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right) ^ { 3 / 4 } = \left( \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 1 / 3 } is

A

13\frac { 1 } { 3 }

B

4

C

9

D

34\frac { 3 } { 4 }

Answer

4

Explanation

Solution

[1+(dydx)2]3/4=(d2ydx2)1/3\left[ 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right] ^ { 3 / 4 } = \left( \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 1 / 3 }[1+(dydx)2]9=(d2ydx2)4\left[ 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right] ^ { 9 } = \left( \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 4 }

Clearly, degree is 4.