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Question

Question: The degree of the differential equation \(\frac { d ^ { 2 } y } { d x ^ { 2 } } + \sqrt { 1 + \left...

The degree of the differential equation

d2ydx2+1+(dydx)3=0\frac { d ^ { 2 } y } { d x ^ { 2 } } + \sqrt { 1 + \left( \frac { d y } { d x } \right) ^ { 3 } } = 0 is

A

1

B

2

C

3

D

6

Answer

2

Explanation

Solution

d2ydx2=1+(dydx)3\frac { d ^ { 2 } y } { d x ^ { 2 } } = - \sqrt { 1 + \left( \frac { d y } { d x } \right) ^ { 3 } }

On squaring, we get

(d2ydx2)2=1+(dydx)3\left( \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 2 } = 1 + \left( \frac { d y } { d x } \right) ^ { 3 }

Obviously the degree is 2.