Question
Question: The degree of Hydrolysis of \(C{{H}_{3}}COON{{H}_{4}}\) is independent of its concentration in solut...
The degree of Hydrolysis of CH3COONH4 is independent of its concentration in solution.
Solution
Degree of Hydrolysis could be defined as the fraction (or percentage) of the total salt which is hydrolyzed at equilibrium.It is generally represented by ‘h’.
h=Total number of moles of salt takenNumber of moles of salt hydrolysed
Also,
h=kh
Where kh= hydrolysis constant
For a given reaction:
A−+H2O⇌HA+OH−
kh=[A−][H2O][HA][OH−]
Since the concentration of H2O is very large, it is practically considered as constant. Therefore,
kh=[A−][HA][OH−]
If the acidity constant(ka) and basicity constant (kb) are provided then,
kh=ka×kbkw
Complete Solution :
The equation of hydrolysis ofCH3COONH4is as follows:
CH3COONH4+H2O⇌CH3COOH+NH4OH
NH4OH⇄NH3+H2O
From the given reactions, it can be observed that CH3COONH4 is obtained from a weak acid (CH3COOH) and a weak base(NH4OH) .
Since the degree of hydrolysis of a salt of weak acid and weak base is given by:
h=kh (For h very small)
h=ka×kbkw
Therefore, the degree of hydrolysis of CH3COONH4 is independent of its concentration.
Note: Salts of strong acids and strong bases do not undergo hydrolysis (they undergo only ionization) hence the resulting aqueous solution is neutral.
- For salts of strong acids and weak bases, the degree of hydrolysis is given by:
h=cKh
- For salts of strong bases and weak acids, the degree of hydrolysis is given by:
h=ka×cKh
Hence for both these types of salts, their degree of hydrolysis is not independent of the concentration .