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Question: The degree of Hydrolysis of \(C{{H}_{3}}COON{{H}_{4}}\) is independent of its concentration in solut...

The degree of Hydrolysis of CH3COONH4C{{H}_{3}}COON{{H}_{4}} is independent of its concentration in solution.

Explanation

Solution

Degree of Hydrolysis could be defined as the fraction (or percentage) of the total salt which is hydrolyzed at equilibrium.It is generally represented by ‘h’.
h=Number of moles of salt hydrolysedTotal number of moles of salt takenh=\dfrac{Number\text{ }of\text{ }moles\text{ }of\text{ }salt\text{ }hydrolysed}{Total\text{ }number\text{ }of\text{ }moles\text{ }of\text{ }salt\text{ }taken}
Also,
h=khh=\sqrt{{{k}_{h}}}
Where kh={{k}_{h}}= hydrolysis constant

For a given reaction:
A+H2OHA+OH{{A}^{-}}+{{H}_{2}}O\rightleftharpoons HA+O{{H}^{-}}
kh=[HA][OH][A][H2O]{{k}_{h}}=\dfrac{[HA][O{{H}^{-}}]}{[{{A}^{-}}][{{H}_{2}}O]}

Since the concentration of H2O{{H}_{2}}O is very large, it is practically considered as constant. Therefore,
kh=[HA][OH][A]{{k}_{h}}=\dfrac{[HA][O{{H}^{-}}]}{[{{A}^{-}}]}
If the acidity constant(ka)({{k}_{a}}) and basicity constant (kb)({{k}_{b}}) are provided then,
kh=kwka×kb{{k}_{h}}=\dfrac{{{k}_{w}}}{{{k}_{a}}\times {{k}_{b}}}

Complete Solution :
The equation of hydrolysis ofCH3COONH4C{{H}_{3}}COON{{H}_{4}}is as follows:
CH3COONH4+H2OCH3COOH+NH4OHC{{H}_{3}}COON{{H}_{4}}+{{H}_{2}}O\rightleftharpoons C{{H}_{3}}COOH+N{{H}_{4}}OH
NH4OHNH3+H2ON{{H}_{4}}OH\rightleftarrows N{{H}_{3}}+{{H}_{2}}O

From the given reactions, it can be observed that CH3COONH4C{{H}_{3}}COON{{H}_{4}} is obtained from a weak acid (CH3COOH)(C{{H}_{3}}COOH) and a weak base(NH4OH)(N{{H}_{4}}OH) .

Since the degree of hydrolysis of a salt of weak acid and weak base is given by:
h=khh=\sqrt{{{k}_{h}}} (For h very small)
h=kwka×kbh=\sqrt{\dfrac{{{k}_{w}}}{{{k}_{a}}\times {{k}_{b}}}}
Therefore, the degree of hydrolysis of CH3COONH4C{{H}_{3}}COON{{H}_{4}} is independent of its concentration.

Note: Salts of strong acids and strong bases do not undergo hydrolysis (they undergo only ionization) hence the resulting aqueous solution is neutral.

- For salts of strong acids and weak bases, the degree of hydrolysis is given by:
h=Khch=\sqrt{\dfrac{{{K}_{h}}}{c}}

- For salts of strong bases and weak acids, the degree of hydrolysis is given by:
h=Khka×ch=\sqrt{\dfrac{{{K}_{h}}}{{{k}_{a}}\times c}}
Hence for both these types of salts, their degree of hydrolysis is not independent of the concentration .