Question
Question: The degree of dissociation of \(Ca{{(N{{O}_{3}})}_{2}}\) in a dilute aqueous solution containing 7g ...
The degree of dissociation of Ca(NO3)2 in a dilute aqueous solution containing 7g of the salt per 100g of water at 100∘C is 70%. If the vapour pressure of water at 100∘C is 760mm, calculate the vapour pressure of the solution.
(A) 378.5mm
(B) 492.8mm
(C) 746.10mm
(D) 985.6mm
Solution
The dissociation degree is the fraction of original solute molecules that have dissociated. It is usually indicated by the Greek symbol α . More accurately, the degree of dissociation refers to the amount of solute dissociated into ions or radicals per mole.
Complete step by step answer:
Given is the degree of dissociation of Ca(NO3)2, is 70%.
Firstly we will calculate the moles of Ca(NO3)2 and water.
Molar mass of Ca(NO3)2 is 164g/mol and mass of Ca(NO3)2 is 7g. Therefore, moles will be,
moles=1647=0.0427moles
Molar mass of water is 18g/mol and mass of water is 100g. Therefore, moles will be,
moles=18100=5.56moles
Now the mole fraction (X) of calcium nitrate will be,
mole fraction=0.0427+5.560.0427=0.00762
The degree of dissociation α =70 % =0.7
The van’t hoff factor will be,