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Question: The degree of dissociation of \(Ca{{(N{{O}_{3}})}_{2}}\) in a dilute aqueous solution containing 7g ...

The degree of dissociation of Ca(NO3)2Ca{{(N{{O}_{3}})}_{2}} in a dilute aqueous solution containing 7g of the salt per 100g of water at 100C{{100}^{{}^\circ }}C is 70%. If the vapour pressure of water at 100C{{100}^{{}^\circ }}C is 760mm, calculate the vapour pressure of the solution.
(A) 378.5mm
(B) 492.8mm
(C) 746.10mm
(D) 985.6mm

Explanation

Solution

The dissociation degree is the fraction of original solute molecules that have dissociated. It is usually indicated by the Greek symbol α\alpha . More accurately, the degree of dissociation refers to the amount of solute dissociated into ions or radicals per mole.

Complete step by step answer:
Given is the degree of dissociation of Ca(NO3)2Ca{{(N{{O}_{3}})}_{2}}, is 70%.
Firstly we will calculate the moles of Ca(NO3)2Ca{{(N{{O}_{3}})}_{2}} and water.
Molar mass of Ca(NO3)2Ca{{(N{{O}_{3}})}_{2}} is 164g/mol and mass of Ca(NO3)2Ca{{(N{{O}_{3}})}_{2}} is 7g. Therefore, moles will be,
moles=7164=0.0427molesmoles=\dfrac{7}{164}=0.0427moles
Molar mass of water is 18g/mol and mass of water is 100g. Therefore, moles will be,
moles=10018=5.56molesmoles=\dfrac{100}{18}=5.56moles
Now the mole fraction (X) of calcium nitrate will be,
mole fraction=0.04270.0427+5.56=0.00762\text{mole fraction=}\dfrac{0.0427}{0.0427+5.56}=0.00762
The degree of dissociation α\alpha =70 % =0.7
The van’t hoff factor will be,

& i=[1+(n-1)\alpha ] \\\ & i=[1+(3-1)0.7] \\\ & i=2.4 \\\ \end{aligned}$$ The relative lowering of the vapour pressure, $$\dfrac{{{P}^{o}}-P}{{{P}^{o}}}=iX$$, where ${{P}^{o}}$ is vapour pressure of the water and P is the vapour pressure of the solution. Substituting the values of pressure, mole fraction and van’t hoff factor, we get, $$\begin{aligned} & \dfrac{760-P}{760}=2.4\times 0.00762=0.018~ \\\ & 760-P=13.9 \\\ & P=746.10mm \\\ \end{aligned}$$ **Therefore, the correct answer is the (C) option.** **Note:** The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.