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Question: The degree of dissociation of an electrolyte is a and its van’t Hoff factor is i. The number of ions...

The degree of dissociation of an electrolyte is a and its van’t Hoff factor is i. The number of ions obtained by complete dissociation of 1 molecule of the electrolyte is:

A

i+α−1α\frac{i + \alpha - 1}{\alpha}

B

i−α−1i - \alpha - 1

C

i−1α\frac{i - 1}{\alpha}

D

1+1+α1−α\frac{1 + 1 + \alpha}{1 - \alpha}

Answer

i+α−1α\frac{i + \alpha - 1}{\alpha}

Explanation

Solution

i = 1 + (n – 1) a so n =i+α−1α\frac{i + \alpha - 1}{\alpha}