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Question: The degree of dissociation of a 0.01 M weak acid is \({10^{ - 3}}\). Its pOH is: A. 5 B. 3 C. ...

The degree of dissociation of a 0.01 M weak acid is 103{10^{ - 3}}. Its pOH is:
A. 5
B. 3
C. 9
D. 11

Explanation

Solution

Weak acids are those which completely do not dissociate in the water when dissolved in it, therefore weak acids are considered as a weak electrolyte.

Complete step by step answer:
The pH is the measurement of acidity and basicity of the solution. The pH scale ranges from 0 to 14. The solutions which give a value less than 7 are said to be acidic and the solutions which give a value more than 7 are said to be basic.
The pH of the solution is defined as the negative logarithm of hydrogen ion.
The equation is given as shown below.
pH=log[H+]pH = - \log [{H^ + }]
The pOH is defined as the negative logarithm of hydroxide ion.
The equation is given as shown below.
pOH=log[OH]pOH = - \log [O{H^ - }]
The dissociation of a weak acid is shown below.
Weak acid (HA)H++A(HA) \rightleftharpoons {H^ + } + {A^ - }
At initial state concentration of weak acid and its dissociated ion will be
C                0                  0C\;\;\;\;\;\;\;\;0\;\;\;\;\;\;\;\;\;0
At equilibrium concentration of weak acid and its dissociated ion will be
CCα                Cα              CαC - C\alpha \;\;\;\;\;\;\;\;C\alpha \;\;\;\;\;\;\;C\alpha
The equilibrium constant of the reaction is given as shown below.
Ka=[Cα][Cα]CCα{K_a} = \dfrac{{[C\alpha ][C\alpha ]}}{{C - C\alpha }}
Ka=Cα2\Rightarrow {K_a} = C{\alpha ^2}(as concentration of α\alpha of weak acid (HA) is very small)
The value of α\alpha is KaC\sqrt {\dfrac{{{K_a}}}{C}}
H+=Cα(Eqi){H^ + } = C\alpha (Eq i)
Substitute the value of α\alpha in the above equation, we get
H+=Ka.C{H^ + } = \sqrt {{K_a}.} C
Given,
Concentration (C) is 0.01 M.
Degree of dissociation (α)(\alpha )is 103{10^{ - 3}}
Substitute the value in equation (i).
H+=0.01×103{H^ + } = 0.01 \times {10^{ - 3}}
H+=105\Rightarrow {H^ + } = {10^{ - 5}}
H+=5\Rightarrow {H^ + } = 5
Depending on the equilibrium concentration of hydrogen ion and hydroxide ion in water, the relation between them is shown below.
pH+pOH=14pH + pOH = 14
To calculate the value of pOH, substitute the of pH in the above equation
pOH=145pOH = 14 - 5
pOH=9\Rightarrow pOH = 9

Therefore, the correct option is C. .

Note: As we can see that in pH there is a negative sign in front of logarithmic. This means that pH is a negative logarithmic scale where a negative sign shows that the pH is in inverse relation with the hydrogen ion.