Question
Question: The degree of dissociation of a 0.01 M weak acid is \({10^{ - 3}}\). Its pOH is: A. 5 B. 3 C. ...
The degree of dissociation of a 0.01 M weak acid is 10−3. Its pOH is:
A. 5
B. 3
C. 9
D. 11
Solution
Weak acids are those which completely do not dissociate in the water when dissolved in it, therefore weak acids are considered as a weak electrolyte.
Complete step by step answer:
The pH is the measurement of acidity and basicity of the solution. The pH scale ranges from 0 to 14. The solutions which give a value less than 7 are said to be acidic and the solutions which give a value more than 7 are said to be basic.
The pH of the solution is defined as the negative logarithm of hydrogen ion.
The equation is given as shown below.
pH=−log[H+]
The pOH is defined as the negative logarithm of hydroxide ion.
The equation is given as shown below.
pOH=−log[OH−]
The dissociation of a weak acid is shown below.
Weak acid (HA)⇌H++A−
At initial state concentration of weak acid and its dissociated ion will be
C00
At equilibrium concentration of weak acid and its dissociated ion will be
C−CαCαCα
The equilibrium constant of the reaction is given as shown below.
Ka=C−Cα[Cα][Cα]
⇒Ka=Cα2(as concentration of α of weak acid (HA) is very small)
The value of α is CKa
H+=Cα(Eqi)
Substitute the value of α in the above equation, we get
H+=Ka.C
Given,
Concentration (C) is 0.01 M.
Degree of dissociation (α)is 10−3
Substitute the value in equation (i).
H+=0.01×10−3
⇒H+=10−5
⇒H+=5
Depending on the equilibrium concentration of hydrogen ion and hydroxide ion in water, the relation between them is shown below.
pH+pOH=14
To calculate the value of pOH, substitute the of pH in the above equation
pOH=14−5
⇒pOH=9
Therefore, the correct option is C. .
Note: As we can see that in pH there is a negative sign in front of logarithmic. This means that pH is a negative logarithmic scale where a negative sign shows that the pH is in inverse relation with the hydrogen ion.