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Question

Physics Question on Moving charges and magnetism

The deflection in a moving coil galvanometer is reduced to half when it is shunted with a 40Ω40\, \Omega coil. The resistance of the galvanometer is

A

80Ω80\, \Omega

B

40Ω40 \, \Omega

C

20Ω20\, \Omega

D

15Ω15 \, \Omega

Answer

40Ω40 \, \Omega

Explanation

Solution

We know, IGI=12\frac{I_{G}}{I}=\frac{1}{2}
SG+S=12\frac{S}{G+S}=\frac{1}{2}
IGI=40G+40=12\frac{I_{G}}{I}=\frac{40}{G+40}= \frac{1}{2}
G=40ΩG=40\, \Omega