Question

The decomposition temperature is maximum for:

\begin{array}{*{20}{l}} {A).{\text{ }}BeC{O_3}} \\\ {B).{\text{ }}Cac{o_3}} \\\ {C).{\text{ }}{K_2}C{O_3}} \end{array} \\\ D).{\text{ }}L{i_2}Co3 \\\ \end{gathered} $$

Answer 1

The decomposition temperature of a substance is that the temperature at which the substance chemically decomposes. The reaction is typically endothermic as heat is required to interrupt chemical bonds within the compound undergoing decomposition. Thermal decomposition, or thermolysis, may be a chemical decomposition caused by heat.

Complete step by step answer:
Thermal stability is $Be,{\text{ }}Mg{\text{ }}and{\text{ }}Ca$ because the ability of a fluid to resist breaking down under heat stress. As such, the utmost use temperature is the suggested maximum temperature to which the fluid will be heated before the fluid begins to interrupt down or degrade at an appreciable rate.
Thermal stability of carbonates increases during a group as we move from top to bottom and reduces in an exceedingly period as we move from left to right, that the correct order of thermal stability of given carbonates is $BeC{O_3} < MgC{O_3} < CaC{O_3} < K_2C{O_3}BeC{O_3} < MgC{O_3} < CaC{O_3} < K_2C{O_3}$
$Be,{\text{ }}Mg{\text{ }}and{\text{ }}Ca$ are present in the second group and K is present in the first group.

So, the correct answer is Option C.

Note: A chemical reaction may be a variety of chemical change within which one compound breaks down into two or more elements or new compounds. samples of decomposition reactions include the breakdown of oxide to water and oxygen, and also the breakdown of water to hydrogen and oxygen.