Question

The decomposition of $N_{2}O_{5}$ is a first order reaction represented by $N_{2}O_{5} \rightarrow N_{2}O_{4} + \frac{1}{2}O_{2}$. After 15 minutes the volume of $O_{2}$ produced is $9ml$ and at the end of the reaction $35ml$. The rate constant is equal to.

• A. $\frac{1}{15}\ln\frac{35}{44}$
• B. $\frac{1}{15}\ln\frac{44}{26}$
• C. $\frac{1}{15}\ln\frac{44}{35}$
• D. $\frac{1}{15}\ln\frac{35}{26}$

Answer 1

Answer: (D)

$\frac{1}{15}\ln\frac{35}{26}$

Answer 2

$K = \frac{1}{t}\log e\left( \frac{a}{a - x} \right) = \frac{1}{15}\log e\left( \frac{35}{35 - 9} \right)$ $= \frac{1}{15}\log e\left( \frac{35}{26} \right)$