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Question: The decay constant of radium is \(4.28 \times 10^{- 4}\)per year. Its half life will be....

The decay constant of radium is 4.28×10−44.28 \times 10^{- 4}per year. Its half life will be.

A

2000 years

B

1240 years

C

63 years

D

1620 years

Answer

1620 years

Explanation

Solution

T=0.6931×1λ=0.6931×14.28×10−4year=1620 6muyearsT = \frac{0.6931 \times 1}{\lambda} = \frac{0.6931 \times 1}{4.28 \times 10^{- 4}}year = 1620\mspace{6mu} years