Question

The de-Broglie wavelength of the electron in the second Bohr orbit is - (given : the radius of the first orbit r₁ = 0.53 Å)

• A. 3.33 Å
• B. 6.66 Å
• C. 9.99 Å
• D. 1.06 Å

Answer 1

Answer: (B)

6.66 Å

Answer 2

2p r = 2ll = p r $= \pi \times 0.53 \times \frac{4}{1}$= 6.66 Å