The de Broglie wavelength of an electron in the (4^{th}) Boh... | Chemistry | SolveeIt

The de Broglie wavelength of an electron in the $4^{th}$ Bohr orbit is :

$6\pi a_{0}$

$2\pi a_{0}$

$8\pi a_{0}$

$4\pi a_{0}$

Answer

$8\pi a_{0}$

Explanation

$2\pi r=n \lambda$
$for\, n=1, r=a_{0}$
$n=4, r=16a_{0}$
$So,\, 2\pi \times16a_{0}=4\times\lambda$
$\lambda=8\pi a_{0}$

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